Interview Question & Answer – 5

Question

Alice and Bob each created one problem for our company. A reviewer rates the two challenges, awarding points on a scale from to for three categories: problem clarity, originality, and difficulty.

We define the rating for Alice’s challenge to be the triplet , and the rating for Bob’s challenge to be the triplet .

Your task is to find their comparison points by comparing with , with , and with .

If , then Alice is awarded point.
If , then Bob is awarded point.
If , then neither person receives a point.
Comparison points is the total points a person earned.

Given and , determine their respective comparison points.

For example, and . For elements , Bob is awarded a point because . For the equal elements and , no points are earned. Finally, for elements , so Alice receives a point. Your return array would be with Alice’s score first and Bob’s second.

Function Description

Complete the function compareTriplets in the editor below. It must return an array of two integers, the first being Alice’s score and the second being Bob’s.

compareTriplets has the following parameter(s):

a: an array of integers representing Alice’s challenge rating
b: an array of integers representing Bob’s challenge rating

Input Format

The first line contains space-separated integers, , , and , describing the respective values in triplet .
The second line contains space-separated integers, , , and , describing the respective values in triplet .

Constraints

Output Format

Return an array of two integers denoting the respective comparison points earned by Alice and Bob.

Sample Input

5 6 7
3 6 10

Sample Output

1 1

Solution

static List<Integer> compareTriplets(List<Integer> a, List<Integer> b) {
    List<Integer> list = new ArrayList<Integer>();
    int aliceCount = 0;
    int bobCount = 0;
    list.add(0, aliceCount);
    list.add(1, bobCount);
    for(int i = 0; i < a.size(); i++){ 
        if(a.get(i) > b.get(i)) {
            list.set(0, ++aliceCount);
        }
        if(a.get(i) < b.get(i)) {
            list.set(1, ++bobCount);
        }
    }
    return list;
}